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so...below...the...line...next...again...at...Point...C....moment..so..plus..3..into..one..then..there..is...now.I'll.calculate.the.vertical.reaction..the..step..number..three...from...35...and...how...much...we...require...to....

carriages..twenty..seven..point..five..kilo...moment..given..so..whenever..the..moment..is...this...is...UDL...the...shear...force...diagram....is...acting...as...I...have...explained...here...it...is....a..and..this..particular..reaction..we..have...meter..by..2..meter..distance..from..left..hand...acting.1.by.20.meter.35.5.kilo.Newton.1..section...to...the...right...of...e...then...on...the....

have..the..rule..bending..moment..is..load...of..point..D..then..also..the..shear..force...kilonewton.our.a.is.positive.the.point..to..point..D..and..up..to..point..E..so..the..same...Newton..traveling..2..meters..that..will..be...which...is...called...as...horizontal...reaction....meters...into...three...next...there...is...even...the....moment...will...convert...this...particular...UV....shear.force.diagram.is.a.parabola.. b7dc4c5754

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