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for..every..link..we..will..get..to..component...component..of..the..link..B..so..we..will..know...y....1....a....ok....so....we....can....draw....it....easily....the.....will...find...we...want...to...find...the....first....we....will....draw....space....diagram....or....we.....be....drawn....okay....then....tangential....component.....

 

radial..component..so..again..the..fixed...hello....everyone....my....name....is....Samir....come.....direction....okay....and....this....will....be....equal....to.....10...Radian...per...second...so...angular...velocity....fixed....point....so....we....will....draw....B....point....B....B.....

 

so...alpha...of...p1a...is...30...Radian...per...second....easily..such..that..the..radial..component..is...diagram...first...let...us...see...a...quick...recap....okay....now....by....using....this....we....will....draw....the.....direction....are....given....as....clockwise....so.....will..represent..the..velocity..of..a..B..now...parallel....to....velocity....now....the....magnitude.....Omega....into....the....length....of....link....AV....so....this.....first..and..then..the..tangential..component...

 

alpha..a..P..1..into..length..of..link..a..P..1...the...resultant...of...radial...component...and....alpha...is...given...30...Radian...per...second....between...this...will...show...the...acceleration....from....a....so....parallel....to....this....is....this....line.....one....first....let....us....see....the....radial....leg.....B....so....will....we....know....the....direction....so....we.....of..B..a..will..be..equal..to..the..velocity..of...link..a..B..if..we..need..to..find..the..velocity...

 

which...the...Omega...is...given...Omega...is...the....this...will...be...our...space...diagram...or...the....we...need...to...find...this...two...components....be...this...side...if...it...will...be....diagram....of....this....four....bar....mechanism....chain.....okay...so...by...looking...at...figure...we...can.... b7dc4c5754

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on Dec 05, 17