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Encontrar La Carga En El Condensador C3 En Coulomb ungarisch bildergallerie lespen schah herscheid

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But which are the forces in this axis?. We can now decompose T in its axys Ty and Tx. Starting by axis Y, we know that the total force is 0.. We have to calculate the value of the load if their mass is 100 grammes.. The electric force and the weight are already decomposed, they go in the directions of the axis.. The value of the hypotenuse is the same as the length of the cable (2m.).. Thank you for your attention!. Firstly, we have to concentrate on one of the forces of the charges: we are going to use Q1.. The symbols + and - come from the cube root because they always have a negative and a positive result.. The mass is 100 gr., that is 0.1 kilo and the gravity is 9.8. The total force, as in axis Y is 0.. Now, we have to calculate axis X. So, T= 1.01 Newtons.. In this way, we have two posible solutions: the two charges are +5.3 · 10^-6 or -5.3 · 10^-6. For those who do not know how to decompose vectors, we add a link to an exercise.. Moreover, we know that this distance is 0.5 metres because the big triangle is isosceles and the distance will be the half of 1m.. We know that Q1 = Q2, so we are going to call this charge Q.. We have named Alpha (a) the angle that the cable makes between Q1 and the vertical.. In this case, we also have to use Coulomb's law to calculate the Electric force, which is K · (Q1·Q2)/r^2.. As we are told that the charges are in balance, there is no force in any axis (0).. In this way, all the forces will be decomposed and we only have to equal them.. In the positive side we have Ty and in the negative one, we have the weight which is 0.. The charges are named by Q1 and Q2.. As we know that the value of T is 1.01, we substitute again.. So, the electric charge over Q1 will go to this direction.. We know that the distance separating them when they are in balance is 1 metre.. Remember that you can contact us by any of our social networks and in www.solucionatusproblemas.es.. As the two charges are the same, the force will be revursive.. Welcome to Solución a tus Problemas. We draw the triangle again in order to clarify the values.. We substitute the values.. Here we have Tx in the positive side and the Electric Force in the negative one.. We draw a triangle. We use arcsine, and we know that Alpha is approximately 14.5º.. So, we have Ty - P= 0 and we use the information for Ty that we achieved before and the formula to calculate the weight, which is mass multiplied by gravity.. Q1 is linked to the floor by a cable and this is named T (Tension).. As we already know Alpha, we are going to solve the values of Tx and Ty.. As in every exercise related to forces, we need axis in order to decompose all the forces.. 9f3baecc53

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